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22:28:02 <lament> woohoo
22:28:14 <Taaus> Whaahaat?
22:28:17 <lament> i proved the [l.count(x) == l[x] for x in range(len(l))] thing
22:28:38 <lament> Unfortunately this channel is too small for me to write it down.
22:28:58 <Taaus> Riight.
22:34:21 <lament> I proved that there's only one solution for len(l) > 7
22:34:35 <lament> (for every len)
22:34:54 <Taaus> For every function?
22:35:08 <lament> um.
22:35:19 <lament> no!
22:35:20 <Taaus> That's wild, man.. I'd expect it to be for every len(l).
22:35:27 <lament> ha.
22:35:34 <Taaus> ;)
22:35:51 <lament> for every N.
22:36:17 <lament> for every N there's only one l such as that len(l) == N and [l.count(x) == l[x] for x in range(N)]
22:36:23 <lament> Where N > 6.
22:38:39 <lament> (THIS is why i haven't written down the proof)
22:39:10 <Taaus> Because you find it difficult to express yourself in precise terms? :P
22:39:20 <lament> Yes.
22:39:38 <Taaus> Ah.
22:39:41 <lament> Math just isn't woozy enough.
22:43:21 <lament> Nor fuzzy!
22:43:30 <lament> Mathematicians can only think inside the box!