00:09:58 <lambdabot> CYUL 180000Z 22007KT 30SM FEW200 BKN270 27/16 A2991 RMK CC1CI6 SLP131 DENSITY ALT 1600FT
00:10:00 <lambdabot> ENVA 172350Z VRB01KT 9999 SCT040 BKN100 12/09 Q1006 RMK WIND 670FT 30005KT
00:10:40 <lambdabot> KOAK 172353Z 31010KT 10SM FEW023 21/12 A2993 RMK AO2 SLP134 T02060117 10211 20172 50001
00:11:11 <lambdabot> *** "hth" vera "V.E.R.A. -- Virtual Entity of Relevant Acronyms (September 2014)"
00:15:20 <boily> helloochaf. mtera???
00:15:56 <lambdabot> *** "tanstaafl" vera "V.E.R.A. -- Virtual Entity of Relevant Acronyms (September 2014)"
00:15:56 <lambdabot> There Ain't No Such Thing As A Free Lunch (slang, Usenet)
00:17:09 <ais523> that blank line at the end of the response is bothering me
00:17:27 <ais523> and I'm not even sure how to send one, I get a 412 when I try
00:17:36 <ais523> there must be an invisible character (other than regular space) somewhere
00:19:02 <boily> split on newlines, drop the last one and print the rest?
00:22:14 <zzo38> Do you like Unuseuset?
00:22:49 <oerjan> . o O ( sounds unuseable )
00:24:02 <oerjan> ais523: pastes as a space in webchat
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00:25:45 <ais523> hmm, maybe my client splits trailing spaces off messages
00:25:53 <ais523> I tried sending a U+0020 space but it didn't work
00:26:08 <ais523> (which is not surprising as one of nbsp's main properties is to be whitespace that is never stripped)
00:29:26 <oerjan> i suppose that also pastes as space.
00:29:57 <oerjan> that was just a space.
00:30:52 <ais523> that was a copy-and-pasted nbsp, I think?
00:31:21 <HackEso> [U+0020 SPACE] [U+0020 SPACE] [U+0020 SPACE]
00:31:26 <ais523> that was a space between two nbsps
00:31:48 <ais523> so either Freenode is translating them (unlikely), or else my client is (also unlikely), or else lambdabot is (more possible?)
00:32:24 <ais523> wait, /that/ was a regular space, and it sent, so perhaps I've forgotten how to type nbsp (or it broke in my recent OS upgrade)
00:41:07 <ais523> nope, same key combination gives me a nbsp in a terminal
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01:29:40 <boily> I wasn't exactly online >_>'...
01:31:51 <boily> I'll be away next weekend (National Holiday). weekend after that I'll be free.
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02:48:42 <zzo38> Unusenet can be useable with NNTP clients. I wrote a document to describe it (available on HTTP and gopher access) that I have mentioned on here before.
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04:02:40 <imode-desktop> so I'm experimenting with using my thue interpreter to do tree rewriting operations.
05:03:25 <zzo38> The specification of Unusenet is at: gopher://zzo38computer.org/0textfile/miscellaneous/unusenet and http://zzo38computer.org/textfile/miscellaneous/unusenet
05:14:37 <imode-desktop> if I was gonna do this easily I'd need a string representation of a tree that enables a node to examine both of its children without leapfrogging over one or the other.
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09:21:04 <shachaf> Taneb: sounds like a tanebventon hth
09:24:34 <Taneb> Oh god what did I invent this time
09:34:45 <shachaf> easily accidentally kicked foot level power sockets
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09:35:38 <Taneb> I deny all responsibility
09:36:11 <shachaf> Taneb inventeth and Taneb taketh away
09:38:40 <Taneb> I'm a victim in all this
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09:50:56 <esowiki> [[Language list]] https://esolangs.org/w/index.php?diff=55884&oldid=55882 * Saka * (+11) /* T */ add
09:52:54 <esowiki> [[Language list]] https://esolangs.org/w/index.php?diff=55885&oldid=55884 * Saka * (+29) some
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15:23:23 <esowiki> [[Talk:]] N https://esolangs.org/w/index.php?oldid=55886 * Plokmijnuhby * (+173) Created page with "Any clues on which instructions pop and which don't would be good. A dup instruction may also be needed. ~~~"
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16:16:03 <\oren\> Anyone know an alternative to Kerberos that isn't as annoying?
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16:37:40 <oerjan> what, this session connected again?
16:39:16 <oerjan> i guess it was only the network having problems, not the server itself, so it finally got back
16:40:42 <oerjan> so tmux survived, and everything was still there. except the email server is still off.
16:41:21 <oerjan> hm no, that worked too after i restarted alpine.
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16:50:01 <quintopia> i have a sequence in mind. a_1=8. a_n is the area of the largest area integer rectangle that can be formed using at most a_{n-1} squares along its border.
16:50:05 <quintopia> the first few terms are 8,9,10,12,16,25,50,182,1980,246016
16:50:06 <zzo38> This has happened before, that I can receive but not send, and restarting the router sometimes fixes it.
16:52:25 <zzo38> Do you know what could be causing such problems? Could it be the weather?
16:57:57 <zzo38> (Also sometimes it works but occasionally is delayed by a few seconds)
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17:19:51 <ATMunn> it's been a while since i've said anything in here
17:28:39 <imode-desktop> I can't imagine what tree or graph structured memory would look like electronically.
17:28:57 <imode-desktop> tree, maybe. you have some analog of it in network equipment.
17:46:46 <int-e> quintopia: wait how do you get that 10?
17:48:44 <int-e> quintopia: I was going to say that a recurrence is easy; you iterate f x = (x+4) `div` 4 * ((x+6) `div` 4) ... but that disagrees with what you claim: starting from 8 it produces 8,9,9,9... and from 10 10,12,16,25,49,169,1849,214369,2872209649,515599267815122569...
17:52:19 <int-e> (equivalently, f x = ((x+4) `div` 2)^2 `div` 4)
17:54:52 <int-e> quintopia: The idea being that with x squares, the circumference will be x+4 (unless one of the rectangle sides is shorter than 2), reducing it to the well-known problem of maximizing the area based on the circumference. There's some rounding because I'm assuming that the sides are constrained to integer lengths.
17:58:46 <quintopia> int-e: you cant make the border of a rectangle with an odd number of squares, so the 10 comes from making a 3x3 square with 8 of the squares, and leaving the 9th one to the side
17:59:03 <quintopia> the middle gets filled in and now you have 10
17:59:18 <quintopia> but i didnt state that asdumption very well originally
17:59:43 <int-e> quintopia: yeah calling it a rectangle is a bit of a stretch
18:00:08 <quintopia> where did you get 49 from in your sequence from 10?
18:02:05 <quintopia> yeah the 49 is from not keeping tbe leftover from the 25
18:02:06 <int-e> quintopia: 24 = 4*6 is enough for a 7x7 square
18:02:56 <quintopia> so its the keeping the extras that makes a formula hard
18:03:12 <int-e> quintopia: okay, doing what you did (setting an extra square aside if x is odd), the sequence becomes 8,9,10,12,16,25,50,182,2162,293222,5373842942,1804886750517122432 ... so we agree until 182
18:03:55 <int-e> f x = ((x+4) `div` 2)^2 `div` 4 + x `mod` 2
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18:06:36 <int-e> ah you compensated by 1 in the wrong direction ending up with 44*45. plausible :)
18:07:56 <quintopia> div means divide and floor, right?
18:08:25 <int-e> > let f x = ((x+4) `div` 2)^2 `div` 4 + x `mod` 2 in iterate f 8
18:08:28 <lambdabot> [8,9,10,12,16,25,50,182,2162,293222,5373842942,1804886750517122432,203601011...
18:08:57 <int-e> my go to language for combinatorics
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18:19:57 <int-e> editing distance 1 is what I see
18:22:17 <quintopia> putting the names of planets in alphabetical order
18:24:20 <int-e> huh, what star are you looking at...
18:26:15 <quintopia> not the first letters of tbeir names
18:26:52 <quintopia> how would i get the general term of the above seqhence?
18:27:52 <int-e> I was never any good at anagrams.
18:29:02 <int-e> imode-desktop: itym lexicographical
18:30:03 <int-e> imode-desktop: in that case, shouldn't it be lexographal?
18:30:19 <int-e> imode-desktop: (I'm not buying your excuse)
18:32:23 <int-e> you are making a good case
18:32:32 <int-e> but it's still hard to believe :P
18:32:43 <int-e> (also, maybe you should get a new keyboard)
18:33:16 <int-e> I don't think that dirt will help.
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18:46:14 <quintopia> i meant the general term of the rectangle sequence
18:46:49 <quintopia> i was hoping for a constant time formula in n
18:48:04 <int-e> quintopia: it's doubly exponential but all that rounding makes things quite messy... I don't expect a nice closed formula
18:54:45 <int-e> I mean ignoring all the rounding you essentially have x |-> x^2 / 16, so you'll end up with a_n = 16 * b^2^n for some base b, asymptotically... b is approximately 1.0193570549183
18:56:09 <int-e> (I start counting at 0, a_0 = 9, a_1 = 10)
18:59:39 <int-e> "asymptotically" meaning it's 16 b^2^(n + o(1)) for some b... it may be 16 b^(2^n + o(1)), but that requires some analysis that I haven't done
19:08:38 <int-e> (and I have no formula for that b, only numerical approximations)
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